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Medan Listrik, Potensial Listrik, dan Kapasitor75Medan Listrik, PotensialListrik, dan KapasitorA. Muatan ListrikB. Medan ListrikC. Energi PotensialListrik danPotensial ListrikD. Kapasitor:-(+?52D6?DED6=29>6>A6=2;2B:>6?86?2:=:CDB:<
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memformulasikan gaya listrik, kuat medan listrik, fluks, potensial listrik, energipotensial listrik, serta penerapannya pada keping sejajar.Setelah mempelajari bab ini, Anda harus mampu:menerapkan konsep kelistrikan dan kemagnetan dalam berbagai penyelesaianmasalah dan produk teknologi.Hasil yang harus Anda capai:75Berbagai jenis kapasitor yang berfungsi untuk menyimpan muatan listrik.Bab4Sumber: Physics for Scientists & Engineers with Modern Physics,2000
Mudah dan Aktif Belajar Fisika untuk Kelas XII76A. Muatan Listrik[email protected]5EA=:<2C:?2C<29@=69>6C:?[email protected]@<@A:>6BEA2<2?C2=29C2DE4@[email protected]2A=:<2C:<@?C6A=:CDB:<CD2D:C52=2><69:5EA2?C692B: 92B:
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1.Interaksi Elektrostatis antara Dua Muatan Listrik%6?:C:?D6B2<C:6=6<[email protected]:C252>242>I2:DE2
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#E<E>D6BC63ED5:<6?2=56?82?1'1)+1(+)#E<E>@E=@>3>6?I2D2<2?329G2Gambar 4.1Mesin fotokopiGambar 4.2Setelah batang karet digosok kainwol dan batang kaca digosok kainsutra kedua batang tersebut tarik-menarik.batang karetbatang karetSumber: Conceptual Physics, 1998"*'*1922*25*1&/&6.0437*5*)&3.786.0!48*37.&1.786.0)&3&5&7.8460*6/&0&31&-74&174&1'*6.098)&1&2'9091&8.-&3Tes Kompetensi Awal
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A2I2?85:>2<CE556?82?>652?=:CDB:<batang karetbatang kacaGambar 4.3Setelah kedua batang karet digosokkain wol dan didekatkan, keduabatang karet tolak-menolak.Gambar 4.4Pada atom hidrogen terdapatsatu proton dan satu elektron.
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OGambar 4.5Interaksi muatan listrik berlainanjenis akan tarik-menarikGambar 4.6Interaksi muatan listrik sejenisakan tolak-menolakContoh 4.1FFq2q1rFFq2q1rFFq2q1Tugas Anda 4.1Anda masih ingat alat yangdinamakan dengan elektroskop?Apakah fungsi alat tersebut?Bagaimanakah cara kerjanya? CobaAnda cari informasi dari internetatau buku-buku referensi.
Mudah dan Aktif Belajar Fisika untuk Kelas XII782.Resultan Gaya Coulomb+6B92D:<2?&2'&6
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>F12q2q1F23F21F32q3r1r2To k o hCharles Coulomb(1736– 1806)Coulomb adalah ahli Fisikakelahiran Angouleme, Prancis. Diamerupakan orang pertama yangmenunjukkan perilaku bahwamuatan listrik saling tolak satu samalain. Namanya kemudian digunakansebagai satuan muatan listrik.Sumber: Jendela IPTEK, 1995---%25:36C2B>E2D2?=:CDB:<5:C6D:2A<6A:?8252=293
3292?F2<E>B) )%25:36C2B82I2@E=@>3?I2252=29)
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Perhatikan gambar berikut.Hitunglah resultan gaya F yangbekerja pada muatan q.qrr–q+qTantanganuntuk Anda
Mudah dan Aktif Belajar Fisika untuk Kelas XII80B. Medan Listrik?52>E?8<:?A6B?29>6?56?82B329G2C6D:2A>E2D2?I2?85:=6D2<<2?5:CE2DE526B292<2?>6>:=:<:>652?=:CDB:<5:C6<:D2B?I2
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Mudah dan Aktif Belajar Fisika untuk Kelas XII822.Resultan Kuat Medan Listrik(652? =:CDB:< >6BEA2<2? 36C2B2? F6<[email protected]
*=69 <2B6?2 :DEA6?;E>=292??I2>6?8:<ED:2DEB2?A6?;E>=292?F6<[email protected]
?5252A2D>6?882>32BF6<[email protected] F6<[email protected]>652?=:CDB:<5:C6<:D2B>E2D2?CD2D:CI2?8>6?E?;E<<2?36C2B52?2B29>652?=:CDB:<A252D:D:< D:D:<5:C6<:D2B>E2D2?D6BC63ED
,6CE=D2?36C2B<E2D>652?5:D:D:<,252=29C63282:36B:<ED
* O&6D6B2?82?<E2D>652?=:CDB:<5:D:D:<,2<:32D>E2D2?-<E2D>652?=:CDB:<5:D:D:<,2<:32D>E2D2?-(652?=:CDB:<>6BEA2<2?36C2B2?F6<[email protected]
*=69<2B6?2:DEE?DE<>6?89:DE?8B6CE=D2?52B:>652?=:CDB:<52A2D5:=2<E<2?56?82?42B2>[email protected]2?2=:C:C>6?88E?2<2?F6<[email protected]C2DE2?2D2E56?82?>6?88E?2<2?>[email protected]8B27:<
([email protected]8B27:<52A2D5:=2<E<2?56?82?CI2B2DC6D:2A>652?=:CDB:<5:<6D29E:2B29F6<[email protected]?I2
Gambar 4.9Titik p dipengaruhi oleh muatanq1 dan q2.&:&'*=69<2B6?2>2CC26=6<DB@?C2?82D<64:=82I236B2D)#52A2D5:232:<2?D6B9252A82I2@E=@>3-:<6D29E:-!O
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Medan Listrik, Potensial Listrik, dan Kapasitor83&:&'2
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82B<E2D>652?=:CDB:<5:D:D:<?@=D6?DE<2?36C2B>E2D2?I2?892BEC5:=6D2<<2?5:D:D:<&:&'*=69<2B6?2---52?
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O --''. -'.-'.-.-.--?682D:7%25:36C2B>E2D2?I2?892BEC5:=6D2<<2?5:D:D:<252=29-DCBAEADEBDEABq1r1 = 5 cm0,2C0,05CPq2E2E1r1 = 5 cmContoh 4.7Pembahasan SoalPada titik-titik sudut B dan Dsebuah bujur sangkar ABCDmasing-masing diletakkan sebuahpartikel bermuatan +q. Agar kuatmedan listrik di titik A = nol, makadi titik C harus diletakkan sebuahpartikel bermuatan sebesar ....a.–qb.+qc.2qd.2qe.22qUMPTN 1991Pembahasan:B(+q)EADEBDEABACD(+q)EAB = EAD = 2kqq = EEBD = 22ABADEE = 22EEBD = 222kqEqEAC = EBD222CkqkqqAC2222Cqqqq2222Cqqqq qC = 22qJawaban: e
Mudah dan Aktif Belajar Fisika untuk Kelas XII843.Hukum Gauss#E<E>"2ECC5:52C2B<2?A252<@?C6A"(1'/
!=E<C252=29<E2?D:D2CI2?8>6?882>32B<2?36B2A232?I2<F6<[email protected]>652?82B:C 82B:C82I2I2?8>6?6>3ECCE2DEA6B>E<22?52=2>2B29D682<=EBEC
+6B92D:<2?&2'&6
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-642B2>2D6>2D:C5:DE=:C<2?C63282:36B:<ED
O&6D6B2?82?7=E<C=:CDB:<)>2D2EG636B<E2D>652?=:CDB:<)=E2C3:52?8I2?85:D6>3EC>652?=:CDB:<>%:<282B:C 82B:C82I2D6BC63ED>6?6>3EC3:52?8D:52<C642B2D682<=EBEC7=E<C=:CDB:<?I2252=29[email protected] O56?82?252=29CE5ED2?D2B2F6<[email protected]>652?52?=E2CA6B>E<22?I2?85:D6>3EC>652?=:CDB:<
2B:<@?C6A7=E<C=:CDB:<:?:=29"2ECC>6?86>E<2<2?9E<E>?I2I2?85:?I2D2<2?C63282:36B:<ED
71)($#.%/#55*#'!(1. .%/101,!.)1'*0!.0101,/!* %*# !*#*&1)($)10*(%/0.%'5*# %(%*#'1,%+(!$,!.)1'*0!.0101,0!./!108-642B2>2D6>2D:C5:DE=:CA6B>E<22?D6BDEDEA-O
Gambar 4.10Garis-garis gaya yangmenembus bidang permukaan.Gambar 4.11Garis gaya yang menembussuatu permukaanmembentuk sudut.#:DE?8=297=E<C=:CDB:<A252CE2DE3:52?8A6BC68:I2?836BE<EB2? P
4>;:<2<E2D>652?=:CDB:<9@>@86?C636C2B
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Medan Listrik, Potensial Listrik, dan Kapasitor854.Perhitungan Medan Listrik dengan Menggunakan HukumGaussa.Medan Listrik pada Keping Sejajar(652?=:CDB:<5:2?D2B2A6=2DC6;2;2B52A2D5:9:DE?856?82?>E529>6?88E?2<2?#E<E>"2ECC
E23E29A6=2D<6A:?8I2?8>6>:=:<:=E2C>2C:?8 >2C:?85:36B:>E2D2?C2>2D6BC632B>6B2D2D6D2A:36B=2G2?2?;6?:CI2:DE-52?O-C6A6BD:A252&2'&6
,2A2D>E2D2?D:2A<6A:?85:567:?:C:<2?C63282:>E2D2?-A6BC2DE2?=E2C -642B2>2D6>2D:C5:DE=:C<2?C63282:36B:<ED
Gambar 4.12Medan listrik antara dua kepingsejajar dengan rapatmuatandan.-O
&E2D>652?=:CDB:<A252A6=2D<@?5E<[email protected]5:D6?DE<2?36B52C2B<2?<@?C6A#E<E>"2ECC
2B2?I256?82?>6>3E2DCE2DEA6B>E<22?D6BDEDEAC6A6BD:C:=:?56BE?DE<>6>E529<2?A6B9:DE?82?
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6?82?56>:<:2?36C2B?I2<E2D>652?=:CDB:<I2?85:D:>3E=<2?@=695E2A6=2D<@?5E<[email protected]5:?I2D2<2?56?82?A6BC2>22?O
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Gambar 4.13Perhitungan kuat medan listrikE pada pelat konduktormenggunakan permukaantertutup (silinder) berdasarkanHukum Gauss.E1A1E2A2E3A3EKata Kunci• medan listrik• garis-garis gaya•fluks• fluks listrik• keping sejajar• bola konduktor• permukaan Gauss
Mudah dan Aktif Belajar Fisika untuk Kelas XII86b.Kuat Medan Listrik pada Bola Konduktor Berongga+6B92D:<2?&2'&6
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52AE?5:52=2>3@=2D:52<D6B52A2D>E2D2?=:CDB:<
6B52C2B<2?#E<E>"2ECC52A2D5:D6?DE<2?36C2B>652?=:CDB:<5:52=2>>2EAE?5:=E2B3@=2I2?836C2B?I2- 2D2E-O
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#2=D6BC63ED5:C6323<2?36C2B?I2>E2D2?I2?85:=:?8<EA:A6B>E<22?"2ECC$-
52AE?E?DE<A6B>E<22?"2ECC$$56?82?.36C2B?I2>E2D2?=:CDB:<I2?85:=:?8<EA:A6B>E<22?"2ECC$$C2>256?82?;E>=29>E2D2?=:CDB:<A2523@=2D6BC63ED
6?82?56>:<:2?>652?=:CDB:<5:A6B>E<22?"2ECC$$252=29---'... &E2D>652?=:CDB:<5:=E2B3@=252A2D5:A6B@=6956?82?>6?82?882A3@=2C63282:>E2D2?=:CDB:<I2?8D6B=6D2<5:AEC2D3@=2
%25:C642B2<6C6=EBE92?>652?=:CDB:<5:C6<:D2B3@=236B@?882252=29M 5:52=2>3@=2 <2B6?2- M 5:A6B>E<22?3@=2-'M 5:=E2BA6B>E<22?3@=2-'.Gambar 4.14Bola konduktor beronggayang memiliki jari-jari R.r = jarak titik ke pusat bola.Gambar 4.15Grafik E terhadap r untukbola konduktor berongga.RaE0r = RrE = 0Tes Kompetensi Subbab B*6/&0&31&-)&1&2'9091&8.-&3
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permukaan Gauss IIpermukaan Gauss I%:<2;2B2<2?D2B2A2BD:<6=
4>5:>2?2<29=6D2<D:D:<I2?8<E2D>652?>28?6D:<?I2?@=
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2qkrE =2qkRE =Rr>Rr<R14 cm–24q–4q20 cm4C4C4C4CdFE
Medan Listrik, Potensial Listrik, dan Kapasitor87
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C. Energi Potensial Listrik dan Potensial Listrik1.Energi Potensial Listrik+6B92D:<2?&2'&6
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Mudah dan Aktif Belajar Fisika untuk Kelas XII882.Potensial Listrik[email protected]?C:2==:CDB:<252=2936C2B?I26?6B8:[email protected]?C:2==:CDB:<A6BC2DE2?>E2D2?
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Contoh 4.10ABCD10 cm6 cm4 cm4 cm4.Hukum Kekekalan Energi Mekanik dalam Medan Listrik#E<E><6<6<2=2?6?6B8:>6<2?:<AE?36B=2<EA25286B2<A2BD:<6=C6A6BD:86B2<[email protected]@?52?6=6<DB@?5:52=2>>652?=:CDB:<
#2=D6BC63ED36B=2<E<2B6?2>652?=:CDB:<>6BEA2<2?>652?<@?C6BF2D:7
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Hukum kekekalan energi mekanikpartikel dalam medan listrik berlakujika pada partikel tersebut tidak adagaya lain yang bekerja selain gayaCoulomb.Ingatlah
Mudah dan Aktif Belajar Fisika untuk Kelas XII90+6B92D:<2?82>32B36B:<ED
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/C292I2?85:=2<E<2?82I2=:CDB:<-E?DE<>6>:?529<2?>E2D2? >E2D2?C6;2E9252=29C636C2B 52AE?52=2>=:CDB:<CD2D:C36C2B?I2EC292252=29-6?82?>6?8823E?8<2?<65E2A6BC2>22?EC292D6BC63ED5:A6B@=69 -- - O O&6D6B2?82?;2B2<2?D2B2<65E2<6A:?8><E2D>652?=:CDB:<0>652[email protected]?C:2=O52A2D5:?I2D2<2?C63282:3652[email protected]?C:2=2?D2B2<65E2<6A:?8C6;2;2B
Gambar 4.19Dua buah keping sejajar danterpisah sejauh d diberimuatan yang sama.Contoh 4.11Kata Kunci• energi potensial listrik• potensial listrik• voltABdEV
Medan Listrik, Potensial Listrik, dan Kapasitor91-63E296=6<DB@?!5:D6>32<<2?>2CE<5:2?D2B25E2<6A:?8C6;2;2B56?82?<646A2D2?2G2=2C6A6BD:A25282>32B36B:<ED
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Contoh 4.12qdxV12d.6?DE<2?[email protected]?C:2=D:D:<5:AEC2DA6BC68::DE;:<22
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q4q3q1q2Ex = ?y = 1 cmVTantanganuntuk AndaSebuah elektron dengan massa9,11 × 10–31 kg dan muatan listrik–1,6 × 10–19 C, lepas dari katodemenuju anode yang jaraknya 2 cm.Jika kecepatan awal elektron = 0 danbeda potensial antara anode dankatode = 200 V, hitunglah kecepatanelektron ketika sampai di anode.
Mudah dan Aktif Belajar Fisika untuk Kelas XII92D. Kapasitor1.Muatan pada Kapasitor+6B?29<29?52>6>6B92D:<2?<@>A@?6? <@>A@?6?I2?82525:52=2>2=2D6=6<DB@?:<C6A6BD:D6=6F:C:52?B25:@&2A2C:[email protected]2D2E<@[email protected]252=29C2=29C2DE<@>A@?6?6=6<DB@?:<I2?82525:52=2>?I2
+6B92D:<2?&2'&6
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?5252A2D>6>32I2?8<2?C63E29EC292E?DE<>6>36B:<2?>E2D2?A252<2A2C:[email protected]56?82?42B2<EDE3[email protected]:D:732D6B2:>6?2B:<6=6<DB@?A252<6A:?8C636=29<:B:9:?882<6A:?8D6BC63ED>6?;25:36B>E2D2?[email protected]:D:752?>[email protected]@?86=6<DB@? 6=6<DB@?D6BC63ED<6<6A:?8C636=29<2?2?>6?;25:36B>E2D2??682D:79:?882<65E2<6A:?8>6>:=:<:>E2D2?C2>292?I2;6?:C?I2I2?836B3652
[email protected]A6BA:?5292?6=6<DB@?52B:<6A:?8<:B:<6<6A:?8<2?2?>6=2=E:6?6B8:&:>:252B:32D6B2:I2?836B=2?8CE?8D6BEC >6?6BECC2>A2:3652[email protected]?C:2=2?D2B2<6A:?8C2>256?82?3652[email protected]?C:2=I2?85:>:=:<:32D6B2:
-2>A2:2<9:B?I2<2A2C:[email protected]D6=29A6?E9>E2D2?52?D:52<52A2D5::C:=28:
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e––+Gambar 4.20Proses pengisian muatanpada kapasitor.kepingkonduktorisolatorkepingkonduktor3EGambar 4.21(a) Jenis kapasitor;(b) Skema kapasitor.22.Kapasitas Kapasitor?52>E?8<:?A6B?29>6=:92D<2A2C:[email protected]D6BED2>252=2>A6B2=2D2?6=6<DB@?:<
%:<2C63E29<2A2C:[email protected]5:9E3E?8<2?56?82?CE>36B3652[email protected]?C:2=I2?836BE329 E329>2<2>E2D2?I2?8D6BC:>A2?5:52=2>?I2AE?36BE329 E329
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Medan Listrik, Potensial Listrik, dan Kapasitor93-O&6D6B2?82?->E2D2?3652[email protected]?C:2=0<2A2C:D2?C:02D2E!&2A2C:D2C<2A2C:[email protected]D:52<5:A6?82BE9:@=69A6BE3292?>E2D2?52?[email protected]?C:2==:CDB:<
52D:82;6?:C<2A2C:[email protected]I2?832?I2<5:8E?2<2?I2:DE2
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Gambar 4.22(a) Kapasitor kertas;(b) Kapasitor variabel;(c) Kapasitor elektrolit.kertaslempeng logamkepingbergerakkeping tetapkapasitor elektrolit-63E29<2A2C:[email protected]5::C:@=6932D6B2:F@=DC69:?88236B>E2D2?
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&6>E5:2?<65E2<2A2C:[email protected]D6BC63ED5:36B:[email protected]?C:2==:CDB:<I2?8C2>236C2B?I2C6A6BD:5:DE?;E<<2?@=69&2'&6
(6=2=E:6<CA6B:>6?D6BC63ED&6&)&;>6>A6B@=6992C:=CA6<D2<E=6B
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Contoh 4.13Tugas Anda 4.2Berdasarkan kepolarannya, dikenaldua jenis kapasitor, yaitu kapasitorpolar dan kapasitor non-polar. CobaAnda cari informasi mengenaiperbedaan di antara keduanya.234
Mudah dan Aktif Belajar Fisika untuk Kelas XII94#&'*1
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)>Gambar 4.24Kapasitor keping sejajardihubungkan dengansumber tegangan V.Gambar 4.23(a) Baterai B menyebabkanperbedaan potensial yang samapada setiap kapasitor; kapasitordengan bahan dielektrik memilikimuatan yang lebih banyak.(b) Kedua kapasitor mengangkutmuatan yang sama. Kapasitordengan bahan dielektrik memilikiperbedaan potensial lebih rendah,seperti ditunjukkan olehpembacaan alat ukur.bahan dielektrikudara23E–q+qVAdSumber: Fundamental of Physics, 2001
Medan Listrik, Potensial Listrik, dan Kapasitor954.Dielektrik pada Kapasitor:2?D2B25E2A6=2D<6A:?8A252<2A2C:[email protected]3:2C2?I25:C:C:A:5:A2C2?8CE2DE3292?:C@[email protected]I2?85:C63ED %!(!'0.%'
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Mudah dan Aktif Belajar Fisika untuk Kelas XII965.Kapasitor Bentuk Bola+6B92D:<2?&2'&6
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[email protected]?C:2=A2523@=2328:2?52=2>5:D:>3E=<2?@=69>E2D2?[email protected]:D:7-52?>E2D2?3@=2328:2?=E2BO-
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&:D2<6D29E:329G2<E2D>652?52?[email protected]?C:2==:CDB:<@=693@=2<@?5E<[email protected]5:D:D:<52?>6>:=:<:A6BC2>22?
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Gambar 4.25Kapasitor bola konsentrisdengan V2 dibumikanR1R2bola 2bola 17
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> Generator Van de Graaff adalah alatuntuk mengumpulkan danmenyimpan muatan listrik statikdalam jumlah yang sangat besar.Rambut wanita ini akan saling tolak-menolak setelah memeganggenerator Van de Graaff dan ujung-ujungnya berdiri karena termuatioleh muatan yang sama.Van de Graff is a tool to collect andstore statics electric chargeenormously in quantity. The woman’shair could be repulsive each otherafter held the Van de Graff generatorand a hair would be repulsivescaused by loading the commoncharges.Informasiuntuk AndaSumber:Physics for You,2001Information for You
Medan Listrik, Potensial Listrik, dan Kapasitor97+6B92D:<2?&2'&6
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!---Contoh 4.15• Kapasitas total dua buah kapasitorseri adalah1212SCCCCC• Perbandingan potensial padakapasitas seri adalah12 312 31111::: ... :::: ... :nnVV VVCC CCIngatlahTugas Anda 4.4Ketika Anda sedang merangkaiperalatan elektronik, kadang-kadangsulit menemukan nilai kapasitaskapasitor yang tepat dengankebutuhan, maka teknik penyusunankapasitor bermanfaat sekali dalamhal ini. Jika Anda hanya memilikikapasitor bernilai besar, susunankapasitor apakah yang akan Andagunakan untuk mendapatkankapasitor bernilai kecil?b.Susunan Paralel2=2>CECE?2?A2B2=6=<2A2C:[email protected]36B=2<E92= 92=36B:<ED
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7.Energi yang Tersimpan dalam Kapasitor&2A2C:D@B;E8236B7E?8C:E?DE<>6?I:>A2?6?6B8:[email protected]?C:2=I2?85:36B:<2?52B:CE>36B[email protected]?C:2==:CDB:<
?6B8:[email protected]?C:2=D6BC63ED5:8E?2<2?<6D:<2B2?8<2:2?=:CDB:<>E=2:36<6B;2
-6;E>=29>E2D2?<652=2><2A2C:[email protected]D6BEC36BD2>329C6=2>2[email protected]A6?8:C:2?D6BEC36B=2?8CE?836BC2>22?56?82?A6BD2>3292?[email protected]?C:2=A252<65E2<6A:?8C6;2;2B9:?882A6?E9C636C2B-Contoh 4.16Tantanganuntuk AndaPerhatikan gambar rangkaiankapasitor berikut.Tentukan:a.kapasitas pengganti antara titikx dan titik y,b.beda potensial antara titik x dany jika muatan pada kapasitor5F adalah 60C.yxC2C13F3F4F4F4F5F3FGambar 4.28Grafik perubahan potensial (V)sebagai fungsi perubahan muatanselama proses pengisianberlangsung.V (V)q(C)qVCGambar 4.27Susunan paralel kapasitorC1C2C3V1V2V3V+–+–+–+–dqQ&6?2:<2?[email protected]=6?6B8:[email protected]?C:2=A252<2A2C:[email protected],252=29A6?;E>=292?2D2E:?D68B2=>E2D2?-!O52B:?@=C2>A2:A6B92D:<2?&2'&6
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Mari Mencari TahuKata Kunci• kapasitas kapasitor• kapasitor kertas• kapasitor variabel• kapasitor elektrolit• farad• kondensator• isolator• dielektrik•katode• anode
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Mudah dan Aktif Belajar Fisika untuk Kelas XII100Rangkuman
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Medan Listrik, Potensial Listrik, dan Kapasitor101Setelah mempelajari bab ini, Anda tentu menjadipaham tentang listrik statis, medan listrik, potensial listrik,energi potensial listrik, kapasitor dan jenis-jenisnya, sertabagaimana cara kapasitor bekerja. Dari semua materipada bab ini, bagian mana yang menurut Anda sulit untukdipahami? Coba Anda diskusikan dengan teman atauguru Fisika Anda.RefleksiPemasangan kapasitor pada sakelar-sakelar listrikyang memiliki daya tinggi dapat menghilangkanterjadinya percikan bunga api. Pemanfaatan ini bergunasekali untuk keamanan. Coba Anda tuliskan manfaat lainpenggunaan kapasitor.9&8&3.786.0>6?:>3E=<2?36BEA2Peta Konsep4@[email protected]A6BC2>22?<E2D>652??I2(652?':CDB:<>6?I:>A2?>6?I6323<2?652[email protected]?C:2=':CDB:<. ?6B8:[email protected]?C:2=':CDB:<,-.(E2D2?.:D:<(E2D2?.6B5:CDB:3EC:M @=2&@?5E<[email protected]M &2A2C:[email protected]
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